Mathematics Grade 9 15 min

Perimeter - Word problems (Advanced)

Perimeter - Word problems (Advanced)

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1

Introduction & Learning Objectives

Learning Objectives Translate complex verbal descriptions of geometric shapes into algebraic expressions and equations. Formulate and solve quadratic equations that arise from word problems involving the perimeter and area of rectangles. Set up and solve perimeter problems where side lengths are represented by polynomial expressions. Analyze and interpret the solutions of equations in the context of a geometric problem, including rejecting non-viable answers (e.g., negative lengths). Solve for unknown dimensions of composite figures or problems involving multiple related perimeters. Determine a shape's perimeter when its dimensions are dependent on the solution to a system of equations. Ever tried to build a custom rectangular fence when you only have enough material fo...
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Key Concepts & Vocabulary

TermDefinitionExample PerimeterThe total continuous distance around the exterior of a two-dimensional closed shape.For a rectangle with sides 5 cm and 3 cm, the perimeter is 5 + 3 + 5 + 3 = 16 cm. Algebraic RepresentationUsing variables (like x) and expressions to represent unknown dimensions of a shape based on verbal descriptions.If 'the length of a rectangle is 5 more than twice its width (w)', the length can be represented as the expression '2w + 5'. Quadratic EquationAn equation that can be written in the standard form ax^2 + bx + c = 0, where a, b, and c are constants and a ≠ 0. These often appear when a problem involves both perimeter and area.A problem might lead to the equation x^2 + 5x - 84 = 0, which can be solved for x to find a dimension. Polynomial Expres...
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Core Formulas

Perimeter of a Rectangle P = 2l + 2w \quad \text{or} \quad P = 2(l + w) Used for any four-sided figure with four right angles. 'l' is the length and 'w' is the width. In advanced problems, 'l' and 'w' will often be algebraic expressions. Perimeter of a Polygon P = s_1 + s_2 + s_3 + ... + s_n The perimeter of any polygon is the sum of the lengths of all its sides. This is used for triangles, pentagons, and other irregular shapes where side lengths might be given as different expressions. The Quadratic Formula x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} A reliable method to solve any quadratic equation in the form ax^2 + bx + c = 0. This is essential when factoring is not straightforward.

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Sample Practice Questions

Easy
A triangle has side lengths represented by the polynomial expressions (x + 7), (3x - 2), and (2x + 3). If the perimeter of the triangle is 44 units, what is the value of x?
A.x = 4
B.x = 5
C.x = 6
D.x = 7
Easy
The verbal description 'the length of a rectangle is 4 meters less than twice its width' is translated into which algebraic expression, where 'w' represents the width?
A.l = 4 - 2w
B.l = 2w - 4
C.l = 2(w - 4)
D.l = w - 4
Easy
A rectangular field has a width of 'x' meters. Its length is 5 meters more than its width. Which equation correctly represents the perimeter, P, of the field?
A.P = 2(x + 5) + 2x
B.P = x(x + 5)
C.P = x + (x + 5)
D.P = 2x(x+5)

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