Mathematics
Grade 9
15 min
Equivalent coins
Equivalent coins
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1
Introduction & Learning Objectives
Learning Objectives
Define direct and inverse variation using the context of coin values and quantities.
Identify the relationship between the number of a specific type of coin and its total value as a direct variation.
Identify the relationship between a coin's denomination and the quantity of coins needed to reach a fixed total value as an inverse variation.
Create equations of variation (y = kx and y = k/x) to model scenarios involving equivalent coins.
Solve for unknown quantities or values in coin-based variation problems.
Set up and solve proportions for direct variation problems involving equivalent coin values.
Ever wonder how many pennies you'd need to have the same value as a pile of quarters? 🪙 Let's explore how direct and inverse variation gives y...
2
Key Concepts & Vocabulary
TermDefinitionExample
Direct VariationA relationship between two variables, x and y, where their ratio is a non-zero constant. As one variable increases, the other increases by a constant factor.The total value (V) of a stack of dimes varies directly with the number of dimes (n). If you have 1 dime, the value is $0.10; for 10 dimes, the value is $1.00. The ratio V/n is always 0.10.
Inverse VariationA relationship between two variables, x and y, where their product is a non-zero constant. As one variable increases, the other decreases.For a total value of $2.00, the number of coins (n) needed varies inversely with the coin's denomination (d). You need 200 pennies (d=$0.01) but only 8 quarters (d=$0.25). The product n × d is always 2.00.
Constant of Variation (k)The non-zero constant i...
3
Core Formulas
Direct Variation Formula
y = kx \quad \text{or} \quad k = \frac{y}{x}
Use this when two quantities increase or decrease together. For coins, this relates the total value (y) of a *specific type* of coin to the number of coins (x). The constant 'k' is the denomination of the coin.
Inverse Variation Formula
y = \frac{k}{x} \quad \text{or} \quad k = xy
Use this when one quantity increases as the other decreases to maintain a constant product. For coins, this relates the number of coins needed (y) to the coin's denomination (x) to reach a *fixed total value*, which is the constant 'k'.
Proportion for Direct Variation
\frac{y_1}{x_1} = \frac{y_2}{x_2}
A practical method to solve direct variation problems without first finding 'k'. If you...
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Challenging
A vending machine requires an exact total value of $1.50. The number of dimes (n_d) needed is 15. The number of quarters (n_q) needed is 6. If the machine was changed to accept a new coin with denomination 'x', and it required 5 of these new coins, what is the value of x?
A.$0.20
B.$0.30
C.$0.40
D.$0.50
Challenging
The number of coins (n) of denomination (d) needed to form a total value (V) is given by the inverse variation n = V/d. If the total value is doubled to 2V and the denomination is halved to d/2, how does the new number of coins (n_new) compare to the original number (n_orig)?
A.n_new = 4 * n_orig
B.n_new = 2 * n_orig
C.n_new = n_orig
D.n_new = 0.25 * n_orig
Challenging
To find the number of nickels (n) needed to make an equivalent value of $12.00, a student correctly identifies this as an inverse variation problem where n = k/d. They calculate the constant of variation k = 12. They are then asked for the final answer. Which common pitfall might lead them to an incorrect choice?
A.Choosing the denomination of a nickel ($0.05) as the answer.
B.Choosing the number of dimes needed (120) as the answer.
C.Choosing the constant of variation (k=12) as the final answer.
D.Choosing the result of 12 / 5 instead of 12 / 0.05.
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