Mathematics Grade 5 15 min

Multiply by 2-digit numbers: complete the missing steps

Multiply by 2-digit numbers: complete the missing steps

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Introduction & Learning Objectives

Learning Objectives Identify and fill in missing digits in partial products when multiplying by 2-digit numbers. Determine missing digits in the final product of a 2-digit multiplication problem. Apply their knowledge of multiplication facts and place value to reconstruct incomplete multiplication problems. Explain the role of the zero placeholder in the second partial product. Use logical reasoning and inverse operations to verify their completed multiplication steps. Accurately perform regrouping (carrying) when finding missing digits in multiplication problems. Ever felt like a detective solving a number mystery? 🕵️‍♀️ Get ready to put on your math hat and uncover the hidden numbers in multiplication problems! In this lesson, you'll become an expert at finding missi...
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Key Concepts & Vocabulary

TermDefinitionExample MultiplicandThe number being multiplied.In $34 imes 12$, the multiplicand is $34$. MultiplierThe number by which another number is multiplied. In this lesson, it's always a 2-digit number.In $34 imes 12$, the multiplier is $12$. Partial ProductThe result of multiplying the multiplicand by one digit of the multiplier. There are two partial products when multiplying by a 2-digit number.For $34 imes 12$: $34 imes 2 = 68$ (first partial product) and $34 imes 10 = 340$ (second partial product). Zero PlaceholderThe zero added in the ones place of the second partial product when multiplying by the tens digit of the multiplier, to show that you are actually multiplying by a multiple of ten.When multiplying $34 imes 12$, for the '1' in '12' (whi...
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Core Formulas

First Partial Product Rule $$\text{Partial Product}_1 = \text{Multiplicand} \times \text{Ones Digit of Multiplier}$$ Multiply the multiplicand by the digit in the ones place of the multiplier. Write this product starting from the ones column. Second Partial Product Rule (Tens Digit) $$\text{Partial Product}_2 = \text{Multiplicand} \times (\text{Tens Digit of Multiplier} \times 10)$$$$ Multiply the multiplicand by the digit in the tens place of the multiplier. Remember to place a zero in the ones column as a placeholder before writing the rest of this product, because you are multiplying by a multiple of ten. Final Product Rule $$\text{Final Product} = \text{Partial Product}_1 + \text{Partial Product}_2$$ Add the two partial products together, aligning them by place v...

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Sample Practice Questions

Challenging
Find the digit that belongs in the star (☆). 7☆ x 53 ---- 231 3850 ---- 4081
A.1
B.3
C.5
D.7
Challenging
When a 2-digit number ending in 9 is multiplied by 24, the second partial product is 1380. What is the final product?
A.1656
B.1380
C.1524
D.1776
Challenging
In the problem A5 × 2B, the first partial product is 105 and the second partial product is 700. What are the digits A and B?
A.A=2, B=5
B.A=3, B=3
C.A=7, B=5
D.A=3, B=5

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