Mathematics
Grade 12
15 min
Trigonometric ratios find an angle measure
Trigonometric ratios find an angle measure
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1
Introduction & Learning Objectives
Learning Objectives
Use inverse trigonometric functions (arcsin, arccos, arctan) to find the principal value of an angle.
Determine all possible angle measures within a given domain (e.g., [0, 2π]) that satisfy a trigonometric equation.
Apply the concept of reference angles to find solutions in all four quadrants.
Solve trigonometric equations involving reciprocal functions (sec, csc, cot) to find angle measures.
Utilize a calculator to find approximate angle measures in both degrees and radians.
Solve for an unknown angle in multi-step problems, including those that first require algebraic manipulation.
Ever wonder how a video game character's aim is calculated or how a satellite orients itself in space? It all comes down to precisely finding angles! 📐
This tutorial...
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Key Concepts & Vocabulary
TermDefinitionExample
Inverse Trigonometric FunctionA function that 'undoes' a trigonometric function. It takes a ratio as input and returns an angle. For example, if sin(θ) = y, then arcsin(y) = θ.If sin(30°) = 0.5, then arcsin(0.5) = 30°.
Principal ValueThe unique angle value returned by an inverse trigonometric function, which lies within a restricted range to ensure it is a true function.The principal value for arccos(-0.5) is 120° or 2π/3, even though cos(240°) is also -0.5. The range for arccos is [0°, 180°].
Reference Angle (α)The acute angle (< 90° or π/2) formed by the terminal arm of an angle θ and the horizontal x-axis. It is always positive.The reference angle for 150° is 30°, because 180° - 150° = 30°. The reference angle for 315° is 45°, because 360° - 315° = 45...
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Core Formulas
Inverse Sine (Arcsine)
If \sin(\theta) = y, then \theta = \arcsin(y) = \sin^{-1}(y). Principal Value Range: [-\frac{\pi}{2}, \frac{\pi}{2}] or [-90°, 90°].
Use this to find the principal angle when you know the sine ratio. Solutions for θ exist only if -1 ≤ y ≤ 1.
Inverse Cosine (Arccosine)
If \cos(\theta) = x, then \theta = \arccos(x) = \cos^{-1}(x). Principal Value Range: [0, \pi] or [0°, 180°].
Use this to find the principal angle when you know the cosine ratio. Solutions for θ exist only if -1 ≤ x ≤ 1.
Inverse Tangent (Arctangent)
If \tan(\theta) = z, then \theta = \arctan(z) = \tan^{-1}(z). Principal Value Range: (-\frac{\pi}{2}, \frac{\pi}{2}) or (-90°, 90°).
Use this to find the principal angle when you know the tangent ratio. Solutions for θ exist for all rea...
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Challenging
Using a calculator, find the approximate solutions for 2cos²(θ) + 4cos(θ) - 1 = 0 in the interval [0, 2π].
A.1.34, 1.80
B.1.34, 4.94
C.0.22, 2.92
D.No solution
Challenging
Find all solutions for the equation sin(2θ) = \frac{\sqrt{3}}{2} in the interval [0, 2π].
A.\theta = \frac{\pi}{6}, \frac{\pi}{3}, \frac{7\pi}{6}, \frac{4\pi}{3}
B.\theta = \frac{\pi}{6}, \frac{\pi}{3}
C.\theta = \frac{\pi}{3}, \frac{2\pi}{3}
D.\theta = \frac{\pi}{3}, \frac{2\pi}{3}, \frac{4\pi}{3}, \frac{5\pi}{3}
Challenging
Find all solutions for sin(θ) - cos(θ) = 1 in the interval [0, 2π].
A.\theta = \frac{\pi}{2}, \frac{3\pi}{2}
B.\theta = 0, \frac{\pi}{2}
C.\theta = \pi, \frac{3\pi}{2}
D.\theta = \frac{\pi}{2}, \pi
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