Mathematics Grade 12 15 min

Solve matrix equations using inverses

Solve matrix equations using inverses

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1

Introduction & Learning Objectives

Learning Objectives Represent a system of linear equations as a matrix equation of the form AX = B. Calculate the determinant of 2x2 and 3x3 matrices to determine if an inverse exists. Find the inverse of a 2x2 matrix using the standard formula. Find the inverse of a 3x3 matrix using the adjoint method. Solve matrix equations of the form AX = B by pre-multiplying by the inverse matrix A⁻¹. Verify the solution of a system by substituting the values back into the original equations. How can we solve a system of 10 equations with 10 variables without endless substitution? 🕵️‍♀️ Matrices provide an elegant and powerful method to do just that! This tutorial will guide you through a systematic process for solving systems of linear equations using matrix inverses. You will learn h...
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Key Concepts & Vocabulary

TermDefinitionExample Matrix EquationAn equation in which a variable stands for a matrix. The most common form for solving systems of linear equations is AX = B, where A is the coefficient matrix, X is the variable matrix, and B is the constant matrix.The system 2x + 3y = 7 and 4x - y = 3 can be written as the matrix equation [[2, 3], [4, -1]] * [[x], [y]] = [[7], [3]]. Identity Matrix (I)A square matrix with 1s on the main diagonal (from top-left to bottom-right) and 0s everywhere else. It is the multiplicative identity for matrices, meaning AI = IA = A.The 2x2 identity matrix is I₂ = [[1, 0], [0, 1]]. The 3x3 identity matrix is I₃ = [[1, 0, 0], [0, 1, 0], [0, 0, 1]]. Inverse Matrix (A⁻¹)For a square matrix A, its inverse A⁻¹ is a unique matrix such that their product is the identity mat...
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Core Formulas

Solution to a Matrix Equation If AX = B, then X = A⁻¹B To solve for the variable matrix X, pre-multiply both sides of the equation by the inverse of the coefficient matrix A. The order of multiplication is critical. Inverse of a 2x2 Matrix For A = \begin{pmatrix} a & b \\ c & d \end{pmatrix}, A^{-1} = \frac{1}{ad-bc} \begin{pmatrix} d & -b \\ -c & a \end{pmatrix} This formula is used to find the inverse of a 2x2 matrix, provided the determinant (ad-bc) is not zero. You swap the elements on the main diagonal, negate the elements on the other diagonal, and multiply the resulting matrix by 1/determinant. Inverse of a 3x3 Matrix (Adjoint Method) A^{-1} = \frac{1}{\det(A)} \text{adj}(A) The inverse of a 3x3 (or larger) matrix is the adjoint of the matrix d...

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Sample Practice Questions

Challenging
Using the matrix inverse method, solve the 3x3 system from the tutorial's worked example: x + 2y + 3z = 3, 2x + 3y + 2z = 3, 3x + 3y + 4z = 7.
A.x = 2, y = -1, z = 1
B.x = 1, y = 1, z = 0
C.x = -1, y = 2, z = 0
D.x = 7, y = -3, z = -1
Challenging
For what value of 'k' does the matrix A = \begin{pmatrix} k & 2 \ 8 & 4 \end{pmatrix} become singular, meaning it has no inverse?
A.k = 2
B.k = 4
C.k = 8
D.k = 16
Challenging
You need to solve AX = B. You are given that det(A) = 5, B = \begin{pmatrix} 10 \ 0 \ 5 \end{pmatrix}, and adj(A) = \begin{pmatrix} 1 & 2 & 3 \ 0 & 5 & -5 \ 4 & -1 & 1 \end{pmatrix}. What is the solution matrix X?
A.\begin{pmatrix} 5 \ -5 \ 9 \end{pmatrix}
B.\begin{pmatrix} 25 \ -25 \ 45 \end{pmatrix}
C.\begin{pmatrix} 5 \ -5 \ 9 \end{pmatrix}
D.\begin{pmatrix} 1 \ -1 \ 1.8 \end{pmatrix}

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