Mathematics Grade 12 15 min

Find tangent lines using implicit differentiation

Find tangent lines using implicit differentiation

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1

Introduction & Learning Objectives

Learning Objectives Differentiate an equation implicitly with respect to x. Correctly apply the chain rule to terms involving y when differentiating with respect to x. Algebraically solve for the derivative, dy/dx, after implicit differentiation. Evaluate the derivative at a specific point (x, y) to find the slope of the tangent line. Write the equation of a tangent line to an implicitly defined curve at a given point using the point-slope form. Identify points where a curve has a horizontal or vertical tangent line by analyzing the derivative dy/dx. How do you find the slope on a curve like a circle, which isn't a standard function? 🤔 Implicit differentiation is the key! This tutorial will teach you how to find the equation of a tangent line for curves that can'...
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Key Concepts & Vocabulary

TermDefinitionExample Implicit RelationAn equation involving two or more variables (like x and y) where one variable is not explicitly solved for in terms of the other.The equation of a circle, x² + y² = 25, is an implicit relation. It's difficult to write it as a single function y = f(x). Explicit FunctionA function where the dependent variable (usually y) is isolated on one side of the equation, explicitly defining it in terms of the independent variable (x).y = 3x² - 2x + 5 is an explicit function. Implicit DifferentiationThe process of finding the derivative of an implicit relation by differentiating both sides of the equation with respect to a variable (usually x), treating the other variable (y) as a differentiable function of x.Differentiating x² + y² = 25 with respect to x yi...
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Core Formulas

Chain Rule for Implicit Differentiation \frac{d}{dx}[f(y)] = f'(y) \cdot \frac{dy}{dx} This is the most critical rule. Whenever you differentiate a function of y with respect to x, you first take the derivative with respect to y, and then multiply by the derivative of y with respect to x (which is dy/dx). Product Rule with Implicit Differentiation \frac{d}{dx}(x \cdot y) = (1 \cdot y) + (x \cdot \frac{dy}{dx}) When differentiating a product of x and y, you must apply the standard product rule. Remember that the derivative of y with respect to x is dy/dx. Point-Slope Form of a Line y - y_1 = m(x - x_1) After finding the slope (m) by evaluating dy/dx at the point (x₁, y₁), use this formula to write the final equation of the tangent line.

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Sample Practice Questions

Easy
When using implicit differentiation with respect to x, what is the correct derivative of the term y³?
A.3y²
B.3y² ⋅ dy/dx
C.3 ⋅ dy/dx
D.y² ⋅ dy/dx
Easy
Which of the following is a key reason for using implicit differentiation?
A.It is faster than explicit differentiation for all functions.
B.It is the only way to differentiate trigonometric functions.
C.It avoids using the chain rule.
D.It can be used when it is difficult or impossible to solve an equation explicitly for y.
Easy
According to the product rule, what is the derivative of the term 'xy' with respect to x?
A.dy/dx
B.y + x ⋅ dy/dx
C.1 ⋅ dy/dx
D.y

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