Mathematics Grade 12 15 min

Find properties of hyperbolas (Tutorial)

Find properties of hyperbolas (Tutorial)

Tutorial Preview

1

Introduction & Learning Objectives

Learning Objectives Identify the center, vertices, and foci of a hyperbola from its standard equation. Determine the orientation (horizontal or vertical transverse axis) of a hyperbola. Derive the equations of the asymptotes for a given hyperbola. Calculate the eccentricity and explain its significance for a hyperbola. Convert the general form of a hyperbola's equation to its standard form by completing the square. Sketch the graph of a hyperbola, accurately plotting its key features and asymptotes. Ever wondered about the shape of a sonic boom's shockwave or the design of a nuclear cooling tower? ✈️ These are real-world examples of the hyperbola we're about to explore! This tutorial will guide you through the key properties of hyperbolas, the final conic sec...
2

Key Concepts & Vocabulary

TermDefinitionExample HyperbolaA set of all points (x, y) in a plane, the difference of whose distances from two distinct fixed points, called foci, is a positive constant.The graph of the equation x²/9 - y²/16 = 1 is a hyperbola. Transverse AxisThe line segment that connects the two vertices of a hyperbola. Its length is 2a.For the hyperbola x²/9 - y²/16 = 1, the transverse axis is horizontal and has a length of 2 * 3 = 6. Conjugate AxisThe line segment perpendicular to the transverse axis, passing through the center. Its length is 2b.For the hyperbola x²/9 - y²/16 = 1, the conjugate axis is vertical and has a length of 2 * 4 = 8. Foci (singular: Focus)The two fixed points used to define the hyperbola. They lie on the same axis as the vertices. The distance from the center to each focus...
3

Core Formulas

Standard Equation of a Horizontal Hyperbola \frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1 Use this form when the transverse axis is horizontal. The center is (h, k). The term with 'a²' is always under the positive variable, and 'a' is the distance from the center to a vertex. Standard Equation of a Vertical Hyperbola \frac{(y-k)^2}{a^2} - \frac{(x-h)^2}{b^2} = 1 Use this form when the transverse axis is vertical. The center is (h, k). The positive term is the y-term, indicating the hyperbola opens up and down. Foci and Asymptotes Relationship Foci: c^2 = a^2 + b^2 \\ Asymptotes (Horizontal): y - k = \pm \frac{b}{a}(x - h) \\ Asymptotes (Vertical): y - k = \pm \frac{a}{b}(x - h) The relationship c² = a² + b² is fundamental for finding the foci. The...

4 more steps in this tutorial

Sign up free to access the complete tutorial with worked examples and practice.

Sign Up Free to Continue

Sample Practice Questions

Challenging
A hyperbola is defined as the set of all points (x, y) where the absolute difference of the distances from (-5, 2) and (9, 2) is 12. What is the standard form equation of this hyperbola?
A.\frac{(x-2)^2}{36} - \frac{(y-2)^2}{13} = 1
B.\frac{(x-2)^2}{49} - \frac{(y-2)^2}{12} = 1
C.\frac{(y-2)^2}{36} - \frac{(x-2)^2}{13} = 1
D.\frac{(x-2)^2}{36} - \frac{(y-2)^2}{49} = 1
Challenging
Find the standard equation of a hyperbola with asymptotes y - 1 = ±\frac{4}{3}(x + 2) and a vertical transverse axis.
A.\frac{(y-1)^2}{9} - \frac{(x+2)^2}{16} = 1
B.\frac{(y-1)^2}{16} - \frac{(x+2)^2}{9} = 1
C.\frac{(x+2)^2}{9} - \frac{(y-1)^2}{16} = 1
D.\frac{(x+2)^2}{16} - \frac{(y-1)^2}{9} = 1
Challenging
A hyperbola has foci at (0, ±√41) and its conjugate axis has a length of 10. What is its standard equation?
A.\frac{y^2}{25} - \frac{x^2}{16} = 1
B.\frac{x^2}{25} - \frac{y^2}{16} = 1
C.\frac{y^2}{16} - \frac{x^2}{25} = 1
D.\frac{x^2}{16} - \frac{y^2}{25} = 1

Want to practice and check your answers?

Sign up to access all questions with instant feedback, explanations, and progress tracking.

Start Practicing Free

More from Conic sections

Ready to find your learning gaps?

Take a free diagnostic test and get a personalized learning plan in minutes.