Mathematics
Grade 12
15 min
Find properties of hyperbolas (Tutorial)
Find properties of hyperbolas (Tutorial)
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1
Introduction & Learning Objectives
Learning Objectives
Identify the center, vertices, and foci of a hyperbola from its standard equation.
Determine the orientation (horizontal or vertical transverse axis) of a hyperbola.
Derive the equations of the asymptotes for a given hyperbola.
Calculate the eccentricity and explain its significance for a hyperbola.
Convert the general form of a hyperbola's equation to its standard form by completing the square.
Sketch the graph of a hyperbola, accurately plotting its key features and asymptotes.
Ever wondered about the shape of a sonic boom's shockwave or the design of a nuclear cooling tower? ✈️ These are real-world examples of the hyperbola we're about to explore!
This tutorial will guide you through the key properties of hyperbolas, the final conic sec...
2
Key Concepts & Vocabulary
TermDefinitionExample
HyperbolaA set of all points (x, y) in a plane, the difference of whose distances from two distinct fixed points, called foci, is a positive constant.The graph of the equation x²/9 - y²/16 = 1 is a hyperbola.
Transverse AxisThe line segment that connects the two vertices of a hyperbola. Its length is 2a.For the hyperbola x²/9 - y²/16 = 1, the transverse axis is horizontal and has a length of 2 * 3 = 6.
Conjugate AxisThe line segment perpendicular to the transverse axis, passing through the center. Its length is 2b.For the hyperbola x²/9 - y²/16 = 1, the conjugate axis is vertical and has a length of 2 * 4 = 8.
Foci (singular: Focus)The two fixed points used to define the hyperbola. They lie on the same axis as the vertices. The distance from the center to each focus...
3
Core Formulas
Standard Equation of a Horizontal Hyperbola
\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1
Use this form when the transverse axis is horizontal. The center is (h, k). The term with 'a²' is always under the positive variable, and 'a' is the distance from the center to a vertex.
Standard Equation of a Vertical Hyperbola
\frac{(y-k)^2}{a^2} - \frac{(x-h)^2}{b^2} = 1
Use this form when the transverse axis is vertical. The center is (h, k). The positive term is the y-term, indicating the hyperbola opens up and down.
Foci and Asymptotes Relationship
Foci: c^2 = a^2 + b^2 \\ Asymptotes (Horizontal): y - k = \pm \frac{b}{a}(x - h) \\ Asymptotes (Vertical): y - k = \pm \frac{a}{b}(x - h)
The relationship c² = a² + b² is fundamental for finding the foci. The...
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Challenging
A hyperbola is defined as the set of all points (x, y) where the absolute difference of the distances from (-5, 2) and (9, 2) is 12. What is the standard form equation of this hyperbola?
A.\frac{(x-2)^2}{36} - \frac{(y-2)^2}{13} = 1
B.\frac{(x-2)^2}{49} - \frac{(y-2)^2}{12} = 1
C.\frac{(y-2)^2}{36} - \frac{(x-2)^2}{13} = 1
D.\frac{(x-2)^2}{36} - \frac{(y-2)^2}{49} = 1
Challenging
Find the standard equation of a hyperbola with asymptotes y - 1 = ±\frac{4}{3}(x + 2) and a vertical transverse axis.
A.\frac{(y-1)^2}{9} - \frac{(x+2)^2}{16} = 1
B.\frac{(y-1)^2}{16} - \frac{(x+2)^2}{9} = 1
C.\frac{(x+2)^2}{9} - \frac{(y-1)^2}{16} = 1
D.\frac{(x+2)^2}{16} - \frac{(y-1)^2}{9} = 1
Challenging
A hyperbola has foci at (0, ±√41) and its conjugate axis has a length of 10. What is its standard equation?
A.\frac{y^2}{25} - \frac{x^2}{16} = 1
B.\frac{x^2}{25} - \frac{y^2}{16} = 1
C.\frac{y^2}{16} - \frac{x^2}{25} = 1
D.\frac{x^2}{16} - \frac{y^2}{25} = 1
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