Mathematics Grade 12 15 min

Exponential growth and decay word problems

Exponential growth and decay word problems

Tutorial Preview

1

Introduction & Learning Objectives

Learning Objectives Model real-world scenarios involving growth and decay using the appropriate exponential functions. Solve for any variable (initial amount, final amount, rate, or time) in an exponential model. Utilize natural logarithms to efficiently solve for time in both discrete and continuous exponential models. Calculate the doubling time or half-life of a quantity and use it to determine the rate constant. Differentiate between discrete (e.g., annual compounding) and continuous (e.g., population growth) models and apply the correct formula. Calculate and interpret the instantaneous rate of change of an exponential model at a specific point in time using derivatives. Ever wonder how scientists date ancient fossils or how a small investment can grow into a fortune?...
2

Key Concepts & Vocabulary

TermDefinitionExample Exponential GrowthA process where a quantity increases at a rate proportional to its current value. The larger the quantity gets, the faster it grows.A bacterial culture that doubles in size every hour. Exponential DecayA process where a quantity decreases at a rate proportional to its current value. The larger the quantity, the faster it shrinks.The value of a new car depreciating by 18% each year. Growth/Decay Rate (r)The percentage change per unit of time, expressed as a decimal. For growth, r is positive; for decay, r is negative.An investment growth rate of 5% per year corresponds to r = 0.05. A radioactive substance decaying at 2% per year corresponds to r = -0.02. Half-LifeThe specific time it takes for a substance undergoing exponential decay to decrease to h...
3

Core Formulas

General Exponential Model (Discrete Intervals) A(t) = A_0 (1 + r)^t Use this for growth (r > 0) or decay (r < 0) that occurs at fixed intervals (e.g., annually, monthly, quarterly). A(t) is the amount after time t, A_0 is the initial amount, r is the rate per interval, and t is the number of intervals. Continuous Growth/Decay Model A(t) = A_0 e^{kt} Use this for phenomena that grow or decay continuously. A(t) is the amount at time t, A_0 is the initial amount, k is the continuous growth rate constant (k > 0 for growth, k < 0 for decay), and t is time. Rate of Change (Derivative of Continuous Model) \frac{dA}{dt} = A'(t) = k \cdot (A_0 e^{kt}) = k \cdot A(t) This formula gives the instantaneous rate of change at any time t. It shows that the rate of c...

4 more steps in this tutorial

Sign up free to access the complete tutorial with worked examples and practice.

Sign Up Free to Continue

Sample Practice Questions

Challenging
Town A has a population of 10,000 and is growing continuously, with a doubling time of 20 years. Town B has a population of 30,000 and is also growing continuously, with a doubling time of 40 years. In approximately how many years will the population of Town A be equal to the population of Town B?
A.31.7 years
B.45.8 years
C.63.4 years
D.80.0 years
Challenging
The population of a city, P(t), grows continuously according to the model P(t) = P_0 e^{kt}. At t=10 years, the population is 100,000, and the instantaneous rate of growth is 2,000 people per year. What was the initial population, P_0?
A.81,873
B.50,000
C.80,000
D.83,333
Challenging
A population of bacteria is growing continuously. The population is measured to be 2,000 at t=3 hours and 8,000 at t=6 hours. What was the initial population of the bacteria at t=0?
A.250
B.500
C.750
D.1000

Want to practice and check your answers?

Sign up to access all questions with instant feedback, explanations, and progress tracking.

Start Practicing Free

More from Exponential and logarithmic functions

Ready to find your learning gaps?

Take a free diagnostic test and get a personalized learning plan in minutes.