Mathematics
Grade 12
15 min
Complex conjugate theorem
Complex conjugate theorem
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1
Introduction & Learning Objectives
Learning Objectives
State the Complex Conjugate Theorem and its conditions.
Identify conjugate pairs of roots for any polynomial with real coefficients.
Construct a polynomial with real coefficients from a given set of complex and real roots.
Use the Complex Conjugate Theorem to find all roots of a polynomial when one complex root is known.
Factor a polynomial into a product of linear and irreducible quadratic factors over the real numbers.
Explain why the theorem requires the polynomial to have real coefficients.
How can a polynomial with only real coefficients produce 'imaginary' answers? 🤔 This theorem reveals the beautiful symmetry behind this paradox!
You will learn about the Complex Conjugate Theorem, a powerful rule that states complex roots of polynomials...
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Key Concepts & Vocabulary
TermDefinitionExample
Polynomial with Real CoefficientsA polynomial P(x) = a_n x^n + a_{n-1} x^{n-1} + ... + a_1 x + a_0 where all the coefficients (a_n, a_{n-1}, ..., a_0) are real numbers.P(x) = 3x^4 - 5x^2 + 2 is a polynomial with real coefficients. Q(x) = 2x^2 + (3i)x - 1 is not.
Complex NumberA number that can be expressed in the form a + bi, where a and b are real numbers and 'i' is the imaginary unit, satisfying i^2 = -1.z = 5 - 2i, where the real part is 5 and the imaginary part is -2.
Complex ConjugateFor a complex number z = a + bi, its complex conjugate, denoted as z̄, is a - bi. The sign of the imaginary part is flipped.The complex conjugate of z = 3 + 4i is z̄ = 3 - 4i.
Root (or Zero) of a PolynomialA number 'c' is a root of a polynomial P(x) if P(c) = 0.F...
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Core Formulas
The Complex Conjugate Theorem
Let P(x) be a polynomial with real coefficients. If a complex number z = a + bi is a root of P(x), then its conjugate z̄ = a - bi is also a root of P(x).
Use this theorem whenever you are given a complex root of a polynomial that has real coefficients. It immediately gives you a second root for free, simplifying the process of finding all roots.
Product of Complex Conjugate Factors
(x - (a + bi))(x - (a - bi)) = x^2 - 2ax + (a^2 + b^2)
This formula is a shortcut for multiplying the linear factors corresponding to a complex conjugate pair of roots. The result is always an irreducible quadratic polynomial with real coefficients.
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Challenging
The polynomial P(x) = x³ + ax² + bx - 51 has real coefficients a and b. If 1 - 4i is a root of P(x), what is the value of 'a'?
A.1
B.-5
C.17
D.-19
Challenging
A polynomial P(x) with real coefficients has a purely imaginary root 3i and a real root -1 with multiplicity 2. The graph of the polynomial passes through the point (1, 40). Find the polynomial.
A.P(x) = x⁴ + 2x³ + 10x² + 18x + 9
B.P(x) = 2x⁴ + 4x³ + 20x² + 36x + 18
C.P(x) = 2x⁴ + 2x³ + 11x² + 18x + 9
D.P(x) = x⁴ + 2x³ + 10x² + 18x - 20
Challenging
Let P(x) = a_n x^n + ... + a_0 be a polynomial with real coefficients. The proof of the Complex Conjugate Theorem relies on which property of complex conjugates?
A.The conjugate of a product is the product of the conjugates: z₁z₂̄ = z₁̄ * z₂̄
B.The conjugate of a sum is the sum of the conjugates: (z₁ + z₂)̄ = z₁̄ + z₂̄
C.The conjugate of a real number is the number itself: k̄ = k for real k.
D.All of the above properties are used in the proof.
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