Mathematics Grade 11 15 min

Solve linear equations: word problems

Solve linear equations: word problems

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1

Introduction & Learning Objectives

Learning Objectives Translate complex verbal descriptions into a system of linear equations. Identify and define unknown quantities as variables in multi-step problems. Set up and solve linear equations for various problem types, including mixture, investment, and distance-rate-time scenarios. Interpret the solution of a system of equations in the context of the original word problem. Verify the reasonableness of a solution by substituting it back into the problem's conditions. Recognize and avoid common errors in setting up and solving linear word problems. An investor wants to split $50,000 between two funds to earn exactly $2,550 in interest. How can you tell them precisely how much to invest in each? 📈 This tutorial bridges the gap between abstract algebra and pra...
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Key Concepts & Vocabulary

TermDefinitionExample VariableA symbol, typically a letter (like x or y), used to represent an unknown quantity or value that can change.In the problem 'A company's profit is twice its cost,' we can define variables: let 'P' represent the profit and 'C' represent the cost. The relationship is P = 2C. Linear EquationAn algebraic equation in which each term is either a constant or the product of a constant and a single variable raised to the first power.The equation C = 25n + 1000 represents the total cost (C) of producing 'n' items, where each item costs $25 and there is a fixed overhead of $1000. System of Linear EquationsA collection of two or more linear equations involving the same set of variables. The solution to the system is the set of v...
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Core Formulas

The Translation Framework Identify Unknowns -> Assign Variables -> Find Constraints -> Formulate Equations -> Solve -> Interpret This is a step-by-step process for tackling any word problem. Systematically breaking the problem down this way prevents confusion and helps ensure all conditions of the problem are met. Distance, Rate, and Time d = rt Used in motion problems. The distance (d) traveled is equal to the rate (r, or speed) multiplied by the time (t) elapsed. This formula can be rearranged to solve for any of the three variables (r = d/t, t = d/r). Simple Interest I = Prt Used in financial problems. The interest (I) earned is the product of the principal amount (P), the annual interest rate (r, as a decimal), and the time (t) in years. Mixtur...

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Sample Practice Questions

Challenging
An amount of money, P, is invested in two accounts with simple interest rates r1 and r2. After one year, the total interest earned is I. If x is the amount invested at rate r1, which expression represents x?
A.(I - P*r2) / (r1 - r2)
B.(I - P*r1) / (r2 - r1)
C.(P*r2 - I) / (r1 + r2)
D.I / (r1 + r2)
Challenging
A chemist has a 30% acid solution and a 70% acid solution. They create a 100 mL mixture that is 42% acid. If they wanted to create a 50% acid solution using the same 100 mL total volume, how would the required amount of the 30% solution change?
A.It would increase by 20 mL.
B.It would decrease by 10 mL.
C.It would decrease by 20 mL.
D.It would increase by 10 mL.
Challenging
A metallurgist has two alloys. Alloy A is 20% gold and Alloy B is 50% gold. They first create a 6 kg mixture (Alloy C) that is 40% gold. They then take 3 kg of Alloy C and mix it with 2 kg of Alloy A to create a new alloy, D. What is the percentage of gold in Alloy D?
A.32%
B.34%
C.36%
D.38%

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