Mathematics Grade 11 15 min

Divisibility rules for 2, 5, and 10

Divisibility rules for 2, 5, and 10

Tutorial Preview

1

Introduction & Learning Objectives

Learning Objectives Algebraically prove why the divisibility rules for 2, 5, and 10 work using polynomial representations of integers. Analyze a polynomial expression P(n) and determine the conditions on the integer variable 'n' that make P(n) divisible by 2, 5, or 10. Decompose variable expressions into components that are demonstrably divisible by 2, 5, or 10 and a remaining component to be analyzed. Construct variable expressions that are always divisible by 2, 5, or 10 for any integer input. Apply the concept of divisibility to solve problems involving sequences and series where terms must meet specific criteria. Evaluate the divisibility of complex algebraic expressions by identifying the controlling term(s). How can we predict if a complex algebraic formula,...
2

Key Concepts & Vocabulary

TermDefinitionExample DivisibilityAn integer 'a' is divisible by a non-zero integer 'b' if there exists an integer 'c' such that a = bc. In the context of expressions, a variable expression P(n) is divisible by 'b' if P(n) = b * Q(n) for some expression Q(n) that yields an integer for any integer 'n'.The expression 10n + 5 is divisible by 5 because it can be factored as 5(2n + 1). Since 'n' is an integer, '2n+1' is also an integer. Polynomial Representation of an IntegerAny integer can be expressed as a sum of powers of 10. This is the basis of our decimal system and is crucial for proving divisibility rules algebraically.The number 483 can be written as 4 * 10^2 + 8 * 10^1 + 3 * 10^0. We can generalize this as N = a_k...
3

Core Formulas

Algebraic Rule for Divisibility by 2 An expression P(n) is divisible by 2 if P(n) \equiv 0 \pmod{2}. For any integer N = 10k + d_0, its divisibility by 2 is determined entirely by its last digit, d_0, because 10k is always divisible by 2. To check if a variable expression is divisible by 2, decompose it into terms that are always even (e.g., multiples of 2, 10, etc.) and analyze the remaining terms. The expression is divisible by 2 if and only if the sum of the remaining terms is divisible by 2. Algebraic Rule for Divisibility by 5 An expression P(n) is divisible by 5 if P(n) \equiv 0 \pmod{5}. For any integer N = 10k + d_0, its divisibility by 5 is determined entirely by its last digit, d_0, because 10k is always divisible by 5. To check if a variable expression is divisibl...

4 more steps in this tutorial

Sign up free to access the complete tutorial with worked examples and practice.

Sign Up Free to Continue

Sample Practice Questions

Easy
According to the algebraic definition of divisibility for variable expressions, the expression P(n) is divisible by 5 if and only if which of the following conditions is met for some expression Q(n) that yields an integer for any integer n?
A.P(n) + 5 = Q(n)
B.P(n) / Q(n) = 5n
C.P(n) = 5 * Q(n)
D.5 * P(n) = Q(n)
Easy
The algebraic proof for the divisibility rule of 2 for any integer N = 10k + d₀ relies on a key property of the term 10k. What is this property?
A.10k is always an odd number.
B.10k is always divisible by 2.
C.10k is only divisible by 2 if k is even.
D.10k is always divisible by 4.
Easy
When analyzing the expression P(n) = 10n² + 3n + 5 to determine its divisibility by 5, which term's divisibility is not guaranteed for all integer values of n?
A.10n²
B.5
C.10n² + 5
D.3n

Want to practice and check your answers?

Sign up to access all questions with instant feedback, explanations, and progress tracking.

Start Practicing Free

More from Variable expressions

Ready to find your learning gaps?

Take a free diagnostic test and get a personalized learning plan in minutes.