Mathematics Grade 10 15 min

Properties of multiplication

Properties of multiplication

Tutorial Preview

1

Introduction & Learning Objectives

Learning Objectives Apply the distributive property to expand the standard form of a circle's equation into its general form. Identify the use of the multiplicative property of zero when calculating the x- and y-intercepts of a circle. Recognize the role of multiplicative factors when completing the square to find a circle's center and radius. Analyze the effect of scalar multiplication on a circle's radius and its corresponding equation. Use the commutative and associative properties to simplify and rearrange algebraic expressions derived from circle equations. Prove that two general form equations are equivalent by identifying a common multiplicative constant. Ever wonder how a simple rule like `a(b+c) = ab + ac` is the key to describing the perfect shape of...
2

Key Concepts & Vocabulary

TermDefinitionExample Distributive PropertyThe property that states multiplying a sum by a number is the same as multiplying each addend by the number and then adding the products.To expand `(x - 5)^2`, we write it as `(x - 5)(x - 5)`. Using the distributive property, this becomes `x(x - 5) - 5(x - 5) = x^2 - 5x - 5x + 25 = x^2 - 10x + 25`. Scalar MultiplicationThe multiplication of a geometric object's parameters (like a circle's radius) by a single number (a scalar). In the context of circles, this results in a dilation.If a circle with radius `r = 3` is dilated by a scalar of 2, the new radius is `r' = 2 * 3 = 6`. Multiplicative Property of ZeroThe property that states the product of any number and zero is zero.To find the y-intercept of a circle, we set `x = 0` in its e...
3

Core Formulas

Standard to General Form Expansion (x - h)^2 + (y - k)^2 = r^2 \rightarrow x^2 + y^2 - 2hx - 2ky + (h^2 + k^2 - r^2) = 0 This conversion is achieved by applying the distributive property to the squared binomials `(x-h)^2` and `(y-k)^2` and then rearranging the terms. It's the primary application of the distributive property in this chapter. Scalar Dilation of a Circle A circle x^2 + y^2 = r^2 dilated by a scalar factor k > 0 becomes x^2 + y^2 = (kr)^2. When a circle centered at the origin is dilated, the new radius is the original radius multiplied by the scalar factor. Note that the term on the right side of the equation is multiplied by `k^2`. Multiplicative Equivalence of General Form Ax^2 + Ay^2 + Bx + Cy + D = 0 \iff k(Ax^2 + Ay^2 + Bx + Cy + D) = 0 For...

4 more steps in this tutorial

Sign up free to access the complete tutorial with worked examples and practice.

Sign Up Free to Continue

Sample Practice Questions

Challenging
The equation k(x - 2)^2 + k(y + 1)^2 = 16 is equivalent to the general form equation 3x^2 + 3y^2 - 12x + 6y - 3 = 0. What must be the value of the scalar k?
A.4
B.3
C.1/3
D.16
Challenging
A student attempts to dilate the circle x^2 + y^2 = r^2 by a scalar k, but incorrectly writes (kx)^2 + (ky)^2 = r^2. This equation simplifies to x^2 + y^2 = (r/k)^2. This error effectively applies a dilation by what multiplicative factor?
A.1/k
B.k^2
C.-k
D.1/k^2
Challenging
To prove that A(x-h)^2 + A(y-k)^2 = Ar^2 is equivalent to the simplified general form for any non-zero A, one must first apply the distributive property to expand the binomials. What is the essential subsequent multiplicative step to complete the proof?
A.Multiply the equation by A
B.Multiply the equation by -1
C.Multiply the equation by 1/A
D.Multiply the equation by r^2

Want to practice and check your answers?

Sign up to access all questions with instant feedback, explanations, and progress tracking.

Start Practicing Free

More from Circles in the coordinate plane

Ready to find your learning gaps?

Take a free diagnostic test and get a personalized learning plan in minutes.