Computer Science
Grade 9
20 min
Lesson 3: Decomposition Practice: Dividing and Conquering
Practice decomposing complex tasks like planning a birthday party or writing a story.
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1
Introduction & Learning Objectives
Learning Objectives
Define the 'Divide and Conquer' algorithmic strategy.
Decompose a complex problem into smaller, independent sub-problems.
Identify the base case in a recursive problem suitable for a Divide and Conquer approach.
Trace the execution of a simple Divide and Conquer algorithm like binary search on a given dataset.
Write pseudocode for a function that uses a Divide and Conquer approach to solve a problem.
Conceptually compare the efficiency of a Divide and Conquer solution to a brute-force approach.
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This lesson introduces a powerful problem-solving technique called 'Divide and Conquer'. You will learn...
2
Key Concepts & Vocabulary
TermDefinitionExample
DecompositionThe process of breaking a complex problem or system into smaller, more manageable parts that are easier to understand, solve, and manage.To build a car, you don't start from a block of metal. You decompose the problem into building an engine, a chassis, wheels, and an interior, then assemble them.
Divide and ConquerAn algorithmic strategy that works by recursively breaking down a problem into two or more sub-problems of the same type, until these become simple enough to be solved directly. The solutions to the sub-problems are then combined to solve the original problem.To sort a deck of 52 cards, you can split it into two piles of 26, sort each of those, and then merge the two sorted piles back together.
RecursionA programming technique where a fun...
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Core Syntax & Patterns
The Three Steps of Divide and Conquer
1. Divide: Break the problem into smaller, independent sub-problems.
2. Conquer: Solve the sub-problems recursively. If a sub-problem is small enough (the base case), solve it directly.
3. Combine: Merge the solutions of the sub-problems to get the final solution.
This is the fundamental template for any Divide and Conquer algorithm. When designing a solution, always think about how your problem fits into these three distinct phases.
Recursive Function Pseudocode Pattern
function solve(problem):
if problem is a base case:
return direct solution
else:
subproblem1, subproblem2 = divide(problem)
solution1 = solve(subproblem1)
solution2 = solve(subproblem2)
return combine(solution1, solution2)
Use this pseudocode st...
4 more steps in this tutorial
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Challenging
Imagine you are designing a Divide and Conquer algorithm to count the number of positive numbers in a list. What would be the correct 'Combine' step?
A.Return `max(count1, count2)` where `count1` and `count2` are the counts from the sub-problems.
B.Return `(count1 + count2) / 2` to find the average count.
C.Return `count1 + count2` where `count1` and `count2` are the counts from the sub-problems.
D.Return `True` if `count1 > 0` or `count2 > 0`.
Challenging
The tutorial states that for binary search, sub-problems are independent. Consider calculating Fibonacci numbers where `fib(n) = fib(n-1) + fib(n-2)`. Why does this recursive approach, while valid, violate the 'independent sub-problems' principle of a pure Divide and Conquer strategy like binary search?
A.Because Fibonacci numbers can only be calculated with loops, not recursion.
B.Because the sub-problems (`fib(n-1)` and `fib(n-2)`) are not of the same type.
C.Because the sub-problems heavily overlap; for example, `fib(n-1)` also needs to calculate `fib(n-2)`, leading to redundant work.
D.Because there is no 'Combine' step in the Fibonacci calculation.
Challenging
A developer defines the base case for finding the maximum in a list as 'a list with 2 or fewer elements'. Why might this be considered less optimal than the standard base case of 'a list with 1 element'?
A.list with 2 elements cannot be a base case because it requires a comparison.
B.This approach would lead to an infinite recursion.
C.It complicates the base case logic and misses the opportunity for one more level of division, slightly altering the algorithm's structure.
D.It is impossible to write code that handles both a 1-element and 2-element list in the same `if` block.
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